XX站~XX站區間/ / 軌道輪子布置地基承載力驗算因根底直接作用于現有砼結構上，所以忽略條形根底擴散作用，作用面積長度為②軌道梁的地基承載力驗算2地基承受的荷載f: KPak2受力模型簡化 彎矩示意圖xx表受拉時，矩形梁受到的最大彎矩為M=64.25kN.m，混凝土上外表受拉時，矩形梁受到的最12HRBfNmmC混凝土軸心抗壓強y度設計值f2,當混凝土強度≤C50時，混凝土受壓區等效矩形應力圖系數a=1.0,當混凝土強c1度≤C50、鋼筋級別為HRB335時，界限相對受壓區高度ξ=0.55。bs0s截面抵抗矩系數a=M=64.25106=0.017h1c0sbsSA==mm2=412.1mm2ys0sA：為截面受力鋼筋的面積sA412.1f1.57A412.1f1.570yminminmin0usy0s0s1c0ssbsSA/==mm2=285.39mm2ys0ssS A/ A/314f1.570yminminmin0usy0sAV=0.7fbh+1.25fsvh,t0yvs0因混凝土等級為C35，所以f2,b=1000mm,h=525mm.t00At0yvs0：可不進行斜截面的受剪承載力計算c sy0s因為x=fAf/A/ysys2?/?fbsuys0s設計資料使用程序:MIDAS/Civil,Civil2006(ReleaseNo.1)截面設計力:3維橋梁級構件制作方法:現澆材料指標量:梁單元10個;柱單元0個點數量:11個邊界條件數量:11個施工階段:2個結構組邊界組荷載組--------合說明MGt輪壓為；龍門吊軌道采用50kg/m鋼軌，龍門吊根底采用40×100cm混凝土根底；龍門吊根底作用在頂板梁上，頂板123282施工階段荷載(CS)1 22永久荷載施工階段荷載(CS)鋼軌荷載+龍門吊根底荷載+頂板荷載序號名稱描述1移動荷載龍門吊移動荷載合說明M]SSo果表格11112222333344IIJJIIJJIIJJIIAX00 44J4J5I5I5J5J6I6I6J6J7I7I7J7J8I8I8J8J9I9I9J9JIIJJ1111111122222222IIIIJJJJIIIIJJJJRbar-1Rbar-1Rbar-1Rbar-1Sig_DL0000Sig_LL0000000000000000DL 33333333444444445555555566666666777777778888888IIIIJJJJIIIIJJJJIIIIJJJJIIIIJJJJIIIIJJJJIIIIJJJRbar-1Rbar-1Rbar-1Rbar-1Rbar-1Rbar-1Rbar-1Rbar-1Rbar-1Rbar-1Rbar-1Rbar-10000000000000000000000000000000000000000000000088J09IRbar-109I09I09I09JRbar-109J09J09J0IRbar-10I0I0I0JRbar-100J00J00J00112233445566778899IJIJIJIJIJIJIJIJIJIJgML0000000000000000000000000000000000000000igMAX00000000000000000000ALW00000000000000000000 單元111122223333444455556666777788889999位置IIJJIIJJIIJJIIJJIIJJIIJJIIJJIIJJIIJJIIJJ最小合計型0000AgREQ_T0000000000000000000000Ag_REQ_B000000000000000000Ag_USE_TB0000000000000000000000000000000000000000 111122223333444455556666777788889999IIJJIIJJIIJJIIJJIIJJIIJJIIJJIIJJIIJJIIJJAg_REQmAg_USE 111122223333444455556666777788889999IIJJIIJJIIJJIIJJIIJJIIJJIIJJIIJJIIJJIIJJ00000000000000000000000000 112233445566778899IJIJIJIJIJIJIJIJIJIJXXXXXXXXXXXXXXXXXXXX 單元1122334455667位置IJIJIJIJIJIJIMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMin0000000000000000000000000000000000000000000000000000000000000000000000000000T-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-MaxMaxVMinT-Max00000000000000000000000000000000000000000000J7J788J8J899J9J9JJ的詳細計算過程:矩形截面驗算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x=(fsd*As-fsd'*As')/(fcd*b)=(330.00*0.00-330.00*25315.50)/(16.10*1000.00)=-518.89mm2as'=1.74mmx＜2as',故x=2as'=1.74mmMnyfsdAs*(h0-as')[混凝土設計原理]= -----------------------------------------------------------------------由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:s-----------------------------------------------------------------------由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.-----------------------------------------------------------------------iMMin: 由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.-----------------------------------------------------------------------jMMin算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.-----------------------------------------------------------------------MMin由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得: x≤ξb*h0并且x≥2as',滿足要求.-----------------------------------------------------------------------MMin由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.----------------------------------------------------------------------i彎矩(M-Min)驗算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得: x≤ξb*h0并且x≥2as',滿足要求.----------------------------------------------------------------------j彎矩(M-Min)驗算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.-----------------------------------------------------------------------MMin由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求. -----------------------------------------------------------------------MMin由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.-----------------------------------------------------------------------iMMin驗算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.---------------------------------------------------------------------- jMMin驗算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.----------------------------------------------------------------------Min由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.-----------------------------------------------------------------------Min 由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.----------------------------------------------------------------------iM-Min)驗算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.-----------------------------------------------------------------------jM-Min)驗算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得: x≤ξb*h0并且x≥2as',滿足要求.-----------------------------------------------------------------------iMMin算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.----------------------------------------------------------------------jM-Min)驗算:由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求. -----------------------------------------------------------------------由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:x≤ξb*h0并且x≥2as',滿足要求.----------------------------------------------------------------------由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:= -------------------------------------------------------------------------由fsd*As=fcd*b*x+fsd'*As'[5.5.2-2]求得:-----------------------------------------------------------------------:cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3] -----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cth Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------h Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cth Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]----------------------------------------------------------------------- hVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]----------------------------------------------------------------------- cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3] -----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cth Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cth Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------=6034.40kNγ0*Vd≤Vn-Sect[5.2.9],抗剪截面滿足驗算要求.Vn-Load=0.50*pow(10,-3)*a2*ftd*b*h0[5.2.10]0.50*pow(10,-3)*1.00*0.00*1000.00*2000.00=0.00kNVcs=a1*a2*a3*0.45*pow(10,-3)*b*h0*sqrt((2+0.6P)*sqrt(fcu,k)*ρsv*fsv)=1.00*1.00*1.10*0.45*pow(10,-3)*1000.00*2000.00*sqrt((2+0.6*0.00)*sqrt(35.00)*(461.70/(200.00*1000.00))*330.00)972.28kNVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]=0.75*pow(10,-3)*330.00*0.00*sin(0.00)=0.00kN-----------------------------------------------------------------------iVMin驗算:Vn-Sect=0.51*pow(10,-3)*sqrt(fcu,k)*b*h0[5.2.9]=0.51*pow(10,-3)*sqrt(35.00)*1000.00*1999.13=6031.77kNctVn-Load=0.50*pow(10,-3)*a2*ftd*b*h0[5.2.10] Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]----------------------------------------------------------------------- cths-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]----------------------------------------------------------------------- cthfsvVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3] ----------------------------------------------------------------------hVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cth Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]----------------------------------------------------------------------cth Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]----------------------------------------------------------------------powsqrt00.00*2000.00=6034.40kNγ0*Vd≤Vn-Sect hVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]----------------------------------------------------------------------- cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3] -----------------------------------------------------------------------hsvVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------hsv Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthsvVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cth Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-------------------------------------------------------------------------h Vsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------hsvVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]----------------------------------------------------------------------- cthVsb=0.75*pow(10,-3)*fsd*Asb*sinθs[5.2.7-3]-----------------------------------------------------------------------rValTorSectnn----------------------------------------------------------------------- rValTorSectnn-----------------------------------------------------------------------mrValTorSect nn-----------------------------------------------------------------------dhrTorValTorSectnn-----------------------------------------------------------------------d rValTorSectnn-----------------------------------------------------------------------krValTorSectnn-----------------------------------------------------------------------i,進展最大剪力(V-Max)時抗扭驗算: krValTorSectnn--------------------------------------------------------------2單i進展最小剪力(V-Min)時抗扭驗算:rValTorSectn n-----------------------------------------------------------------------i,進展最大扭矩(T-Max)時抗扭驗算:dhrTorValTorSectnn-----------------------------------------------------------------------j,進展最大剪力(V-Max)時抗扭驗算:tdhrTorValTorSect nn-----------------------------------------------------------------------j,進展最小剪力(V-Min)時抗扭驗算:krValTorSectnn-----------------------------------------------------------------------j,進展最大扭矩(T-Max)時抗扭驗算:k rValTorSectnn-----------------------------------------------------------------------i最大剪力(V-Max)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------i最小剪力(V-Min)時抗扭驗算: rValTorSectnn-----------------------------------------------------------------------i大扭矩(T-Max)時抗扭驗算:rValTorSect nn-----------------------------------------------------------------------j大剪力(V-Max)時抗扭驗算:dhrTorValTorSectnn-----------------------------------------------------------------------j最小剪力(V-Min)時抗扭驗算:dhrTorValTorSect nn-----------------------------------------------------------------------j最大扭矩(T-Max)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------i構件處理),進展最大剪力(V-Max)時抗扭驗算: krValTorSectnn-----------------------------------------------------------------------i構件處理),進展最小剪力(V-Min)時抗扭驗算:dhrTorValTorSect nn-----------------------------------------------------------------------i構件處理),進展最大扭矩(T-Max)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------j構件處理),進展最大剪力(V-Max)時抗扭驗算:WtrValTorSect nn-----------------------------------------------------------------------j構件處理),進展最小剪力(V-Min)時抗扭驗算:rValTorSectn-----------------------------------------------------------------------j構件處理),進展最大扭矩(T-Max)時抗扭驗算: rValTorSectnn-----------------------------------------------------------------------i最大剪力(V-Max)時抗扭驗算:rValTorSectnn -----------------------------------------------------------------------i最小剪力(V-Min)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------i最大扭矩(T-Max)時抗扭驗算:rValTorSect nn-----------------------------------------------------------------------j最大剪力(V-Max)時抗扭驗算:mrValTorSectnn-----------------------------------------------------------------------j最小剪力(V-Min)時抗扭驗算: rValTorSectnn-----------------------------------------------------------------------j最大扭矩(T-Max)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------i),進展最大剪力(V-Max)時抗扭驗算: rValTorSectTdt0.5nn-----------------------------------------------------------------------i),進展最小剪力(V-Min)時抗扭驗算:dhrTorValTorSect nn-----------------------------------------------------------------------i),進展最大扭矩(T-Max)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------j),進展最大剪力(V-Max)時抗扭驗算: rValTorSectnn-----------------------------------------------------------------------j),進展最小剪力(V-Min)時抗扭驗算:mrValTorSectnn-----------------------------------------------------------------------j),進展最大扭矩(T-Max)時抗扭驗算: krValTorSectnn-----------------------------------------------------------------------i剪力(V-Max)時抗扭驗算:rValTorSectn n-----------------------------------------------------------------------i剪力(V-Min)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------i扭矩(T-Max)時抗扭驗算:rValTorSect nn-----------------------------------------------------------------------j剪力(V-Max)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------j剪力(V-Min)時抗扭驗算: rValTorSectnn-----------------------------------------------------------------------j扭矩(T-Max)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------i理),進展最大剪力(V-Max)時抗扭驗算: rValTorSectnn-----------------------------------------------------------------------i理),進展最小剪力(V-Min)時抗扭驗算:rValTorSect nn----------------------------------------------------------------------i理),進展最大扭矩(T-Max)時抗扭驗算:rValTorSectTdt5nn-----------------------------------------------------------------------j理),進展最大剪力(V-Max)時抗扭驗算:rValTorSect nn-----------------------------------------------------------------------j理),進展最小剪力(V-Min)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------j理),進展最大扭矩(T-Max)時抗扭驗算: rValTorSectnn-----------------------------------------------------------------------i),進展最大剪力(V-Max)時抗扭驗算:rValTorSectnn -----------------------------------------------------------------------i理),進展最小剪力(V-Min)時抗扭驗算:dhrTorValTorSectnn-----------------------------------------------------------------------i理),進展最大扭矩(T-Max)時抗扭驗算:tdhrTorValTorSect nn-----------------------------------------------------------------------j理),進展最大剪力(V-Max)時抗扭驗算:rValTorSectnn-----------------------------------------------------------------------j理),進展最小剪力(V-Min)時抗扭驗算: rValTorSectnn--------------------------------------------------