1、答案僅供參考1、 改錯(cuò)題1. 找出以下兩處邏輯錯(cuò)誤（非編程規(guī)范）并改正 char* getErrorString(int errcode)char errorString = "not exist" char errorString2 = "not available"switch(errcode) case 1: return errorString; case 2: return errorString2; default: return NULL;void printErrorString(int errcode)char *errorString

2、 = getErrorString(errcode);printf("errcode:%d, errorString:%sn", errcode, errorString); case1和case2返回了兩個(gè)局部變量指針，而局部變量在函數(shù)結(jié)束后將自動(dòng)釋放。改正：將字符數(shù)組改為指針 char *errorString= "not exist" char *errorString2 = "not available"2. 以下是輸出“welcome home”的程序，找出邏輯錯(cuò)誤（非編程規(guī)范）并改正 const int MAX_STR_S

3、IZE = 12; int main(int argc, char *argv) char strMAX_STR_SIZE; strcpy(str,"welcome home"); printf("%s", str);return 0; “welcome home”字符串應(yīng)該是13個(gè)字節(jié)，而str字符數(shù)組只能存儲(chǔ)12個(gè)字符 改正： const int MAX_STR_SIZE = 13;2、 程序填空題1. 寫出String類的構(gòu)造函數(shù)，析構(gòu)函數(shù)和賦值函數(shù) class Stringpublic:String(const char *str = NULL)

4、;String(const String &other);String();String& operator =(const String &other);private:char *m_data;String:String()(1)delete m_data;String:String(const char *str)if( (2)str=NULL ) m_data = (3)new char;*m_data = 0;else int length = (4)strlen(str);m_data = new charlength+1;strcpy(m_data, st

5、r);String& String:operator =(const String &other)if( (5) this = other) return (6)*this;(7) delete m_data;int length = strlen( (8)other );m_data = new charlength+1;(9)strcpy(m_data,other.m_data)return (10)*this;2. 一個(gè)計(jì)算到指定年份有多少個(gè)“黑色星期五”（當(dāng)月的13號并且是星期五)的程序，具體忘了。3、 編程題1. 實(shí)現(xiàn)以下函數(shù)，把給定string中的和替換成(和)st

6、d:string replace(std:string &str) for(int i = 0; i < str.size();i+) if(stri='') stri='(' if(stri='') stri=')' return str;2. 實(shí)現(xiàn)函數(shù)，使數(shù)字num按B進(jìn)制輸出int main(int argc, char *argv)long num = 134;int B = 8;func(num, B);return 0;例如134按2進(jìn)制輸出10000110，按8進(jìn)制輸出206，按十六進(jìn)制輸出86void func(long num,int B) int a100 =0; int count=0; while(num>0) acount+=num%B; /保存余數(shù) num=num/B; for(int i = count - 1; i >=0; i-) /逆序輸出 if(ai>=10)/十六進(jìn)制