（理科：必修選修Ⅱ）44．第Ⅰ卷（選擇題，共B第Ⅰ卷（選擇題共60分）5bi(1i)(a,bR)abia則2ii2i2i．．．．MaMNM，Na2aa,a,aa2,則n1244．6．8．10．xy≤4,y≤2,則2xxyzxyx≥1135．7．．．fxfxx(xR)f(x)2．sinxsinx．cosxcosx．．．．1xD．．()fxfxfxx,0．0,1,0．．．(x)21f(x)1x1fx0(x)0xf(x)≥0．xf．．1110000(x)0xf(x)≤0．xf10000Axx2y3122．4．5．32126D．x2y30yx22xy302xy10．．．．2xy102xy3023621．．．．223RrrR與rrR2rRrR6r．．R．．第Ⅱ卷（非選擇題共90分）45.1b2aa+baa、ba，且與b．5AC4，BCABC6,AB．85a615aax2．x612242x2xx,x66ABCCACB1，且ABC°111ACBA451AA1CAACB.11xx≤x≤，P、Qfx2PQfxMx1、y1將數(shù)字4334xFCDCDM、N．yF2MN(nN)ann1．*n1aa1nn1ba2nbbbb2n1．a(chǎn)123nnnn理科數(shù)學(xué)試題參考答案及評分標(biāo)準(zhǔn)5題號123456789選項(xiàng)BBAADACBABCDbi(1i)2ia0,b22abii．a(chǎn)∴2BMNM．a(chǎn)aa2a4a4．2a221422．yoxA(1,-1)在fxsinxcosx．．fx222異面時(shí)所成或11或12面對角線異面時(shí)所成角的度數(shù)是D．CAB1x001fxxfx.xxfx0(x)log(x1)(x,f(x))．f111200001CAx121314ACr．y222y302是，設(shè)切點(diǎn)為x,yBx，00x22x2x2x1,y1.則yox000012x1y．A'(-1,-1)B'x2y21C'(2,-3)上的點(diǎn)P坐標(biāo)為ab221a26aa,1abb3(ac)2ace222a22222．224b23,O,OOR123C,CHOOOOOOr121231232R23RCOHCHOOH1311112233COCHOHRrrRR6r．2故212221111r1H3245．．3．50．13a+baa+b0aab=0a1故ab=1，a2ab12ab∴,∴與a．b3ab1135ABACsinA654,sinA．SA，2245∵CAcosA2A9，∴BC3．2228550CCCC58565856arC(x)()12r0r4得()15aa1.aC．TaCxrr令26r123r446rr16x66cos2xcos2xcos2cosxsin2sinxcos2cosxsin2sinx666666112sin2xsinsin2xsin2x622,2x,2xx即又x，∴242612tantan3134xtantan23∴==．分1234131tantan34ACB90ACCBAAABCACCB1°1ACAACBA1ACA4511AACAAC90AC1AA1在Rt6分111CAABCABCBCCAAACCAC1111111∴BCAACC1BCACCAACB1.分111ACB90ABCABC111m設(shè)AA1C,A,B,Cm,Am11mCBCC0,0,mCA，，，110,0,mABCCC，10acm0n11cACBn=1由0bn0n=manmCBA4545，A111nmm211AA1得m∴6分1CA1CA0CACACA，111111CA0CACB∴CAACB.分1111,yx,yyxxyxx，P、Qx，212211221122yyx2xxx22xxxxxx1=k112=121212xx1xxxx1221212,xxx1xx11.∵x且，∴121212.5分,yx1d1xMxMx00010My1d1y20則ddd1x1y=1x1xx21x2=x3012000000632≤d0，ddx20x036x1d0當(dāng)，d306469ddd1．x分3012．141113=P；22,=aba，b3ab32、、、a且是，41P2；12A24∴12333,,3ab=abca3abc3、、是、，41；24P3A34∴24644,,,a3ab=abcd、、abc34,2、、、，、614P24A44∴．244∴123414131614P29E分12、CDF．:ykx1y4x22xk20設(shè)lkxk2222AB2222kxxk22xMB，ykx1M,．k∴A2kkk2MM221ABkN2k1,2kCD①當(dāng)kMk22kx2kk1l:y2k，2k222k12k2；1kykx3MN即2T②當(dāng)k1MNx3MNT．7分kyBMCoxTANDk，22k2,21,2M，Nk2kk22211k22212k2kk∴k242k2kk4k21919222222≥224kkk222kkk24242221k14．分k2k2．）aaaaa1(nN)a0,a1,i1,2,*123nniia1aaaaa1a(nN)則aaa2，13nn123n1n11a1an1a，n11a2an1nn1121a1．∴n1a1n1a1a11nn2an111a.121n1可得∴是以為首項(xiàng)，為公差的等差數(shù)列，在已知中令∴a11a1n11n(n1)(n1a6分a1a11nnn11nn1nn1a22n