1、名稱編程題2_數據及教師學生類備注描述題目描述：有五個類，各類的主要數據成員見下方說明，請自己定義合理的成員函數，編程實現體現該繼承 關系的程序，并定義教師對象、學生對象、研究生對象、在職研究生對象，輸出他們的信息。關于數據成員：數據類Data :成員name 保存姓名；/該類是Teacher類和Student類的基類教師類Teacher :增加成員sal保存工資；學生類Student :增加成員id保存學號； 該類是PostGrad 類的基類研究生類PostGrad :增加成員dn保存系別；教師中的在職研究生類 Tpost ：不另外定義數據成員。該類有兩個直接基類：Teacher類和研 究生

2、類PostGrad關于成員函數：每個類中均定義輸出所有數據成員的函數void print ()。具體代碼可參考主函數及對應的輸出結果樣例來完成。主函數代碼如下：int main ()Teacher tobj("Zhuhong”, 2000);Student sobj("Wanghui", "B05030417");PostGrad pobj("Lixuefeng", "Yj040217", "Computer Department");Tposttpobj("Liuling&

3、quot;, "Yz040318", "Society Department", 800);cout << "the teacher:n"tobj.print ();cout << "nthe student:n"sobj.print ();cout << "nthe postgraduate:n"pobj.print ();cout << "nthe teacher and postgraduate:n"tpobj.print

4、 ();return 0;提示：(1)最前面需要作相應的文件包含(2)請注意類之間的繼承關系，可能存在虛基類在保存并預覽之后，點 開：“測試用例”選項 卡，再選擇卜方的“添 加”，加入兩組測試測試用例，無輸入部分： 輸出部分：the teacher: Name:Zhuhong sal=2000the student: Name:Wanghuiid=B05030417the postgraduate: Name:Lixuefeng id=Yj040217 dn=Computer Departmentthe teacher and postgraduate: Name:Liuling sal=80

5、0id=Yz040318dn=Society Department參考源程序代碼#include <iostream>#include <string> using namespace std; class Data public: Data(char *na) name = new charstrlen(na)+1; strcpy(name, na);Data() delete name;參考源代碼僅供老師參考 加到系統中，不要添void print()cout << "Name:" << name << end

6、l;protected:char *name;；class Student: virtual public Datapublic:Student(char *na, char *pid): Data(na) id = new charstrlen(pid)+1; strcpy(id, pid);Student()delete id;void print()Data二print();cout << "id=" << id << endl;protected:char *id;；class Teacher: virtual public Da

7、tapublic:Teacher(char *na, float psal): Data(na)sal = psal;void print()Data二print();cout << "sal=" << sal << endl;protected:float sal;class Postgrad: public Studentprotected:char *dn;public:Postgrad(char *na, char *pid, char *p): Data(na), Student(na, pid) dn = new charst

8、rlen(p)+1;strcpy(dn, p);Postgrad()delete dn;void print()Student:print();cout << "dn=" << dn << endl;；class Tpost: public Teacher, public Postgradpublic:Tpost(char *na, char *pid, char *p, float psal): Data(na), Teacher(na, psal), Postgrad(na,pid,p);void print()Teacher二pri

9、nt();cout << "id=" << id << endl;cout << "dn=" << dn << endl;int main()Teacher tobj("Zhuhong”, 2000);Student sobj("Wanghui", "B05030417");Postgrad pobj("Lixuefeng", "Yj040217", "Computer Departm

10、ent");Tpost tpobj("Liuling", "Yz040318", "Society Department", 800); cout << "the teacher:n"tobj.print();cout << "nthe student:n"sobj.print();cout << "nthe postgraduate:n"pobj.print();cout << "nthe teacher and postgraduate:n"tpobj.print();return