




版權說明:本文檔由用戶提供并上傳,收益歸屬內容提供方,若內容存在侵權,請進行舉報或認領
文檔簡介
1、/#pragma warning (disable: 4786)/#pragma comment (linker, "/STACK:16777216")/HEAD#include <cstdio>#include <ctime>#include <cstdlib>#include <cstring>#include <queue>#include <string>#include <set>#include <stack>#include <map>#include
2、<cmath>#include <vector>#include <iostream>#include <algorithm>#include <time.h>#include <cstdlib>using namespace std;typedef long long LL;const double MAX_VAL = (double)1e18;const int MAX_GEN = 30;/最大迭代次數const int MAX_SCALE = 3000;/最大種群規模const int MAX_CITY = 20 +
3、 2;/最大城市數const double W_VAL = 0.729;/struct SO int x, y; SO() SO(int x, int y): x(x), y(y);struct Point double x, y; Point() Point(int x, int y):x(x), y(y); void read() scanf("%lf%lf", &x, &y); ;inline int randomI(int x) return rand()%x; inline double randomD() return (double)rand(
4、)/RAND_MAX; inline double getDist(Point a, Point b) return sqrt(a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y);struct PSO double w; int scale; int cityNum; int nowGen;/當前代數 int maxGen;/迭代次數 int bestNum; int bestGen;/最佳出現代數 double distMAX_CITYMAX_CITY; int oPopMAX_SCALEMAX_CITY;/粒子群 double fitn
5、essMAX_SCALE;/種群適應度,表示種群中各個個體的適應度 vector<SO> listVMAX_SCALE;/ 每科粒子的初始交換序列 int PdMAX_SCALEMAX_CITY;/一顆粒子歷代中出現最好的解, double vPdMAX_SCALE;/解的評價值 int PgdMAX_CITY;/ 整個粒子群經歷過的的最好的解,每個粒子都能記住自己搜索到的最好解 double vPgd;/ 最好的解的評價值 PSO() PSO(int s, int c, int mG, double ww, double dMAX_CITYMAX_CITY) scale = s;
6、 cityNum = c; maxGen = mG; w = ww; for (int i = 0; i < cityNum; i+) for (int j = 0; j < cityNum; j+) distij = dij; void copyArray(double a, double b, int n) for (int i = 0; i < n; i+) ai = bi; void copyArray(int a, int b, int n) for (int i = 0; i < n; i+) ai = bi; void init() nowGen = 0;
7、 for (int i = 0; i < scale; i+) for (int j = 0; j < cityNum; ) int x = randomI(cityNum); int r; for (r = 0; r < j; r+) if (x = oPopir) break; if (r = j) oPopij = x;/ cout << oPopij << ' ' j+; / cout << endl; for (int i = 0; i < scale; i+) / cout << i <&
8、lt; " :" << endl; int vn = randomI(cityNum) + 1; for (int j = 0; j < vn; j+) int x = randomI(cityNum); int y = randomI(cityNum); while (x = y) y = randomI(cityNum); SO so(x, y); listVi.push_back(so);/ cout << so.x << "*" << so.y << ' ' / c
9、out <<endl; getFitness(); for (int i = 0; i < scale; i+) vPdi = fitnessi; copyArray(Pdi, oPopi, cityNum); bestNum = 0; vPgd = fitness0; bestGen = 0; for (int i = 0; i < scale; i+) if (vPgd > fitnessi) vPgd = fitnessi; bestNum = i; copyArray(Pgd, oPopbestNum, cityNum); double getVal(in
10、t x) double ret = 0; for (int i = 0; i < cityNum; i+) int xx = oPopxi % cityNum; int yy = oPopx(i + 1) % cityNum; ret += distxxyy; return ret; void getFitness() for (int i = 0; i < scale; i+) fitnessi = getVal(i); void UpdateVal() int j = 0; double vj = fitness0; for (int i = 0; i < scale;
11、i+) if (vPdi > fitnessi) vPdi = fitnessi; copyArray(Pdi, oPopi, cityNum);/? if (vj > fitnessi) vj = fitnessi; j = i; if (vj < vPgd) bestGen = nowGen;/ bestNum = j;/ vPgd = vj; copyArray(Pgd, oPopj, cityNum); void changeTo(int a, vector<SO> v)/ int vn = v.size(); for (int i = 0; i <
12、 vn; i+) int x = vi.x, y = vi.y; swap(ax, ay); vector<SO> minus(int a, int b)/ int cMAX_CITY, dMAX_CITY; for (int i = 0; i < cityNum; i+) di = bi; for (int i = 0; i < cityNum; i+) cai = i; vector<SO> v; SO s; for (int i = 0; i < cityNum; i+) if (di != ai) s.x = i, s.y = cai; swa
13、p(ds.x, ds.y); v.push_back(s); return v;void addTo(vector<SO> &v, vector<SO> a, int vn) for (int i = 0; i < vn; i+) v.push_back(ai); / Vii=wVi+ra(Pid-Xid)+rb(Pgd-Xid) void evolution() for (int ig = 0; ig < maxGen; ig+) nowGen = ig + 1;/nowGen for (int is = 0; is < scale; is+
14、) if (is = bestNum) continue; vector<SO> v; v.clear(); int lvn = w * listVis.size(); addTo(v, listVis, lvn); vector<SO> a = minus(Pdis, oPopis); int an = randomD() * a.size(); addTo(v, a, an); vector<SO> b = minus(Pgd, oPopis); int bn = randomD() * b.size(); addTo(v, b, bn); listVi
15、s = v; changeTo(oPopis, listVis);/ cout << listVis.size() << endl; getFitness(); UpdateVal(); void solve() init(); evolution(); printf("answer %lf:n", vPgd); printf("solution n"); for (int i = 0; i < cityNum; i+) if (i) printf(" "); printf("%dn"
16、, Pgdi); cout << bestGen << ' ' << bestNum << endl; puts(""); ;int cn;vector<Point> pv;double dMAX_CITYMAX_CITY;void pre(vector<Point> pv) int cn = pv.size(); for (int i = 0; i < cn; i+) for (int j = i + 1; j < cn; j+) dij = dji = getDist(p
17、vi, pvj); int main () srand(unsigned long)time(0); /設置時間種子 while (cin >> cn) pv.clear(); for (int i = 0; i < cn; i+) Point p; p.read(); pv.push_back(p); pre(pv); PSO solver(MAX_SCALE, cn, MAX_GEN, W_VAL, d); cout << "*" << endl; solver.solve(); cout << "*&qu
18、ot; << endl; return 0;/ cout << nowGen << " -:" << endl;/ for (int i = 0; i < scale; i+)/ / cout << vPdi << ' ' << fitnessi << endl;/ for (int j = 0; j < cityNum; j+)/ cout << Pdij << ' '/ cout << endl;/ / for (int i = 0; i < scale; i+)/ / for (int j = 0; j < listVi.size(); j+)/ cout << listVij.x << "*" << listVij.y << ' '/ cout << endl;/ / cout << vPgd << ' ' << bestGen << &
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯系上傳者。文件的所有權益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網頁內容里面會有圖紙預覽,若沒有圖紙預覽就沒有圖紙。
- 4. 未經權益所有人同意不得將文件中的內容挪作商業或盈利用途。
- 5. 人人文庫網僅提供信息存儲空間,僅對用戶上傳內容的表現方式做保護處理,對用戶上傳分享的文檔內容本身不做任何修改或編輯,并不能對任何下載內容負責。
- 6. 下載文件中如有侵權或不適當內容,請與我們聯系,我們立即糾正。
- 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 企業食堂凍貨管理制度
- 飛利浦公司內部管理制度
- 企業債權債務管理制度
- 酸堿質子理論如何定義酸和堿
- 企業活動舉辦管理制度
- 上海購房相關管理制度
- 人員招聘解聘管理制度
- 鄉村就業工場管理制度
- 鄉鎮學校自主管理制度
- 企業假期薪酬管理制度
- 教師教學對話分析方案T-SEDA可編輯模板
- 國開《人工智能專題》終考試題及答案
- 增材制造技術發展課件
- 市級課題結題報告-“雙減”背景下小學數學課堂開展學生“項目式學習”的實踐研究(優秀等次)
- 暨南大學《馬克思主義基本原理概論》題庫歷年期末考試真題分類匯編及答案
- DB44-T 2267-2021《公共機構能源資源消耗限額》-(高清現行)
- DLT 1055-2021 火力發電廠汽輪機技術監督導則
- 青霉素的發現與作用課件
- 學校后勤服務滿意度調查問卷
- 施工進度計劃網絡圖、橫道圖
- 雙梁歐式電動葫蘆橋式起重機使用說明書
評論
0/150
提交評論