1、最新2022年全國高考化學題分類匯編(熱化學計算)of rural drinking water sources, protection of drinking water sources in rural areas by the end of the delimitation of the scope of protection, complete with warning signs, isolating network protection facilitiesof rural drinking water sources, protection of drinking water s

2、ources in rural areas by the end of the delimitation of the scope of protection, complete with warning signs, isolating network protection facilitiesof rural drinking water sources, protection of drinking water sources in rural areas by the end of the delimitation of the scope of protection, complet

3、e with warning signs, isolating network protection facilities熱化學計算(2022重慶)答案：D2022四川卷1116分3： 25、101kpa時，Mn(s)O2(g)MnO2(s) H520kJ/molS(s)O2(g)SO2(g) H297kJ/molMn(s)S(s)2O2(g)MnSO4(s) H1065kJ/molSO2與MnO2反響生成無水MnSO4的熱化學方程式是_。2022新課標I28、(15分)2：甲醇脫水反響2CH3OH(g)CH3OCH3(g)H2O(g)H123.9KJmol1甲醇制烯烴反響2CH3OH(g)C

4、2H4 (g)2H2O(g) H229.1KJmol1乙醇異構化反響CH3CH2OH(g)CH3OCH3(g) H3+50.7KJmol1那么乙烯氣相直接水合反響C2H4 (g)H2O(g)C2H5OH(g)的H -45.5KJmol12022廣東B3116分用CaSO4代替O2與燃料CO反響，既可提高燃燒效率，又能得到高純CO2，是一種高效、清潔、經濟的新型燃燒技術，反響為主反響，反響和為副反響。CaSO4(s)+CO(g) CaS(s)+CO2(g) H1= 47.3kJmol-1 CaSO4(s)+CO(g) CaO(s)+CO2(g) +SO2(g) H2= +210.5kJmol-1

5、 CO(g) C(s)+ CO2(g) H3= 86.2kJmol-1 1反響2CaSO4(s)+7CO(g) CaS(s)+ CaO(s)+6CO2(g)+ C(s) +SO2(g)的H_用H1、H2和H3表示2022北京：2NO2g N2O4gH1 2NO2g N2O4lH2 以下能量變化示意圖中，正確的選項是選填字母_。 A B CN2O4與O2、H2O化合的化學方程式是_。2022廣西28(15分)化合物AX3和單質X2在一定條件下反響可生成化合物AX5。答復以下問題：1AX3的熔點和沸點分別為93.6 和76 ，AX5的熔點為167 。室溫時AX3與氣體X2反響生成lmol AX5，

6、放出熱量123.8 kJ。該反響的熱化學方程式為 。2022新課標II13、室溫下，將1mol的CuSO45H2O(s)溶于水會使溶液溫度降低，熱效應為H1，將1mol的CuSO4(s)溶于水會使溶液溫度升高，熱效應為H2；CuSO45H2O受熱分解的化學方程式為：CuSO45H2O(s) eq o(=,sup5()CuSO4(s)+5H2O(l)， 熱效應為H3。那么以下判斷正確的選項是A、H2H3 B、H1H3C、H1+H3 =H2 D、H1+H2 H32022江蘇10：C(s)O2(g)CO2(g) H1CO2(g)C(s)2CO(g) H22CO(g)O2(g)2CO2(g) H34F

7、e(s)3O3(g)2Fe2O3(s) H43 CO(g)Fe2O3(s)3CO2(g)2Fe(s) H5以下關于上述反響焓變的判斷正確的選項是AH10，H30BH20，H40CH1H2H3DH3H4H52022海南4、標準狀況下，氣態分子斷開1mol化學鍵的焓變稱為鍵焓。HH，HO，和O=O鍵的鍵焓H分別為436KJ/mol，463KJ/mol，495KJ/mol，以下熱化學方程式正確的選項是 A、H2O(g)=H2(g)+1/2O2(g) H =485KJ/molB、H2O(g)=H2(g)+1/2O2(g) H = + 485KJ/molC、2 H2(g) + O2(g)=2 H2O(g) H = + 485KJ/molD、2 H2(g) + O2(g)=2 H2O(g) H =485KJ/mol 【答案】D【解析】根據“HH，HO，和O=O鍵的鍵焓H分別為436KJ/mol，463KJ/mol，495KJ/mol，可以計算出2mol H2和1mol O2完全反響生