1、asm遺傳算法求解集運模型48004 BCD440042CQ400038003600340032CQ3 DOO_o 2oo 400 m son iodo 1200 noo ieoo iboo 2000 進化代數clc;clear;%各份訂單基本數據phen=12 3 4 5 6 7 8 9 10 11 12 13 1441,52,-23,-46,-143,-74,-56,101,73,74,95,86,-35,3265,23,-76,104,34,38,4,-23,55,-49,39,89,-86,527716,9887,12188,8819,4002,6119,3284,4607,5600,

2、4587,9821,13024,6547,2684500,400,1000,120,0,235,654,241,0,361,120,254,300,1501,4,2,2,4,4,3,3,3,1,4,5,1,32.7,1.8,4,2.5,1.6,1,3.6,5,4.2,1.9,6.4,2.8,1.4,8;hromle ngth=14;popsize=30;maxge n=500;pc=0.8;pm=0.04;for kem=1:popsizepopulatio n( kem,:)=ra ndperm(hromle ngth);endpopulatio n;%評價目標函數值for uim=1:po

3、psizevector=populatio n(uim,:);obj(uim)=ha nshu(hromle ngth,vector,phe n); end%obj%mi n(obj)clear uim;objmi n=mi n( obj);for sequ=1:popsizeif obj(sequ)=objminopti=populatio n( sequ,:);endendclear sequ;fmax=22000;%=for gen=1:maxgen%選擇操作%將求最小值的函數轉化為適應度函數for indivi=1:popsizeobj1(i ndivi)=1/obj(i ndivi)

4、;endclear indivi;%適應度函數累加總合total=0;for indivi=1:popsizetotal=total+obj1(i ndivi);endclear indivi;%每條染色體被選中的幾率for indivi=1:popsizefit ness1(i ndivi)=obj1(i ndivi)/total;endclear indivi;%各條染色體被選中的范圍for indivi=1:popsizefit ness(i ndivi)=0;for j=1:indivifit ness(i ndivi)=fit ness(i ndivi)+fit ness1(j);e

5、ndendclear j;fitn ess;%選擇適應度高的個體for ranseti=1:popsizeran=rand;while (ran>1|ran<0)ran=rand;endran;if ran<=fitness(1)n ewpopulati on (ran seti,:)=populati on( 1,:);elsefor fet=2:popsizeif (ran>fitness(fet-l)&&(ran<=fitness(fet)n ewpopulati on(ran seti,:)=populatio n( fet,:);ende

6、ndend end n ewpopulati on;%交叉for int=1:2:popsize-1popmoth=n ewpopulati on (i nt,:);popfath=newpopulati on (i nt+1,:); popcross(i nt,:)=popmoth;popcross(i nt+1,:)=popfath; randnum=rand;if(randnum< P>cpo in t1=r oun d(ra nd*hromle ngth);cpo in t2=r oun d(ra nd*hromle ngth); while (cpoint2=cpoint

7、1)cpoi nt2=ro un d(ra nd*hromle ngth); endif cpoint1>cpoint2tem=cpo in t1;cpo in t1=cpo int2;cpo in t2=tem;end cpo inti;cpo int2;for term=cpoint1+1:cpoint2for ss=1:hromlengthif popcross(int,ss)=popfath(term)temi=popcross(i nt,ss);popcross(i nt,ss)=popcross(i nt,term);popcross(i nt,term)=temi;ende

8、ndendfor term=cpoint1+1:cpoint2for ss=1:hromlengthif popcross(int+1,ss)=popmoth(term)tem1=popcross(i nt+1,ss);popcross(i nt+1,ss)=popcross(i nt+1,term);popcross(i nt+1,term)=tem1;endend clear teml;endendclear term;end popcross;%變異操作 n ewpop=popcross;for int=1:popsizerandnum=rand;if randnumcpoi nt12=

9、ro un d(ra nd*hromle ngth);cpoi nt22=ro un d(ra nd*hromle ngth);if (cpoint12=0)cpoi nt12=1;end if (cpoint22=0)cpoi nt22=1;end while (cpoint22=cpoint12)cpoi nt22=ro un d(ra nd*hromle ngth);if cpoint22=0;cpoi nt22=1;endend temp=n ewpop(i nt,cpo in t12);n ewpop(i nt,cpo in t12)=n ewpop(i nt,cpo in t22)

10、;n ewpop(i nt,cpoi nt22)=temp;end end n ewpop;clear cpoint12;clear cpoint22;clear randnum;for ium=1:popsizevector仁 newpop(ium,:);obj1(ium)=ha nshu(hromle ngth,vector1,phe n); endclear ium;obj1max=max(obj1);for ar=1:popsizeif obj1(ar)=obj1maxn ewpop(ar,:)=opti;endendclear population;clear objmin;clea

11、r objmean;%遺傳操作結束populati on=n ewpop;for ium=1:popsizevector2=populatio n(ium,:);obj(ium)=object(hromle ngth,vector2,phe n);end objmi n=mi n(obj);objmea n=mea n(o bj);clear opti;for sequ1=1:popsizeif obj(sequ1)=objminopti=populatio n( sequ1,:);end end solutio n=objmi n;fin al1(ge n)=o bjmea n;end op

12、ti soluti on plot(fi nal);hold on;plot(fi nail,'-') hold off%目標函數值子函數fun ctio ncost=ha nshu(hromle ngth,vector,phe n) wmax=20000;ct=1.2;ch=0.5;for num=1:hromlengthli ne=vector( nu m);s(:, num )=phe n( :,li ne);endm=1;cshort=0;chold=0;ctran s=0;while m<=hromlengthj=m;weight=s(4,j);day=s(6,j);dis=sqrt(s(2,j)A2+s(3,j)A2);while (j< P>weight=weight+s(4,j+1);if (s(6,j+1)< P>cshort=(s(5,j+1)*(s(7,j+